-220t=-10t^2

Solution for -220t=-10t^2 equation:

-220t=-10t^2

We move all terms to the left:

-220t-(-10t^2)=0

We get rid of parentheses

10t^2-220t=0

a = 10; b = -220; c = 0;
Δ = b2-4ac
Δ = -2202-4·10·0
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{48400}=220$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-220)-220}{2*10}=\frac{0}{20}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-220)+220}{2*10}=\frac{440}{20}
=22
$